怎么设计2018年日历，用Java语言编写个日历程序

本文目录一览

1，用Java语言编写个日历程序
2，用C语言设计一个年历系统急今晚做出的加50分
3，C语言程序设计万年历打印设计
4，电子万年历用C语言设计一个年历系统功能要求 1输入任一

1，用Java语言编写个日历程序

class CalendarListint year,month; int dayNum,i,num,count=0; Calendar objCalendar; int[] arrDayNum=; CalendarList()objCalendar=Calendar.getInstance(); this.year=objCalendar.get(Calendar.YEAR); this.month=objCalendar.get(Calendar.MONTH)+1; //要+1 } CalendarList(String args0,String args1)this.year=Integer.parseInt(args1); this.month=Integer.parseInt(args0); objCalendar=Calendar.getInstance();//这里没有get objCalendar.set(Calendar.YEAR,year);//set是这样用的 objCalendar.set(Calendar.MONTH,month-1); } void display()System.out.println("\t\t\t"+year+"年"+month+"月"); System.out.println("日一二三四五六"); //每个空3个空格num=objCalendar.get(Calendar.DAY_OF_WEEK); if ((year/4==0&&year/100!=0)||(year/400==0))arrDayNum[1]+=1; } for (i=1;i<=12;i++)if (i==month)dayNum=arrDayNum[i-1]; break; } } for(i=1;i<=num;i++)System.out.print(" ");//5个空格 count++; } for (i=1;i<=dayNum;i++)System.out.print(i<10?" "+i+" ":i+" "); //自己改了下 ,空格数:1,3,3count++; if(count==7)System.out.println(); count=0; } } System.out.println (); } } public class MainClass public static void main(String[] args) CalendarList objCalendar=new CalendarList(); CalendarList objCalendar1=new CalendarList("11","2007"); objCalendar.display(); objCalendar1.display(); } }

额好撒! 等着!! java 编写一个日历应该不难吧

用Java语言编写个日历程序

2，用C语言设计一个年历系统急今晚做出的加50分

只说一句话，去CSDN上找！

#includestatic int year; static int weekday; bool isleapyear(int y) //判断是否是闰年 { return(y%4==0&&y%100!=0||y%400==0); //闰年的条件就是年份同时能被4和100整除或 // 者能被400整除 } long firstdayofyear(int y) //求出输入的那年第一天是星期几 { long n; n=y*365; for(int i=1;i if(isleapyear(i)) n+=1; return n%=7; } void printhead(int m) //打印每个月的标题 { if(m<10) printf(" %d月日一二三四五六\n",m); else printf(" %d月日一二三四五六\n",m); printf(" "); for(int i=0;i printf(" "); } int daysofmonth(int m) // 判断每个月有多少天 { switch(m) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: return 31; case 4: case 6: case 9: case 11: return 30; case 2:if(isleapyear(year)) return 29; else return 28; } return 0; } void printmonth(int m) //打印每月的日历 { printhead(m); int days=daysofmonth(m); for(int i=1;i<=days;i++) { if(i<10) printf(" %d",i); else printf(" %d",i); weekday=(weekday+1)%7; if(weekday==0) { printf("\n"); printf(" "); } } } void main() //主程序入口，接收输入的年份，调用函数打印日历 { int y; printf("请输入年份："); scanf("%d",&y); year=y; if(year<1) { printf("输入年份不能小于1\n"); return; } weekday=(int)firstdayofyear(year); printf(" %d年\n",year); printf(" ========================================\n"); for(int i=1;i<=12;i++) { printf("\n"); printmonth(i); printf("\n"); } } 可以显示公元1世纪以后的所有年份的日历，第2和第3问其实都包含在第1问里，程序看懂了自然也就会了（话说为什么不能上传附件？）

用C语言设计一个年历系统急今晚做出的加50分

3，C语言程序设计万年历打印设计

以下程序来源《C精粹（第2版）》 #include "stdio.h"#include "stdlib.h"long int f(int year,int month) if(month<3) return year-1; else return year;} long int g(int month) if(month<3) return month+13; else return month+1;} long int n(int year,int month,int day) /*N=1461*f(年、月)/4+153*g(月)/5+日*/ return 1461L*f(year,month)/4+153L*g(month)/5+day;} int w(int year,int month,int day) /*w=(N-621049)%7(0<=w<7)*/ return(int)((n(year,month,day)%7-621049L%7+7)%7);} int date[12][6][7];int day_tbl[ ][12]= main() int year;/*年*/ char title[]="SUN MON TUE WED THU FRI SAT"; clrscr(); system("cls");printf("Please input the year whose calendar you want to know: ");/*输入年*/scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/sw=w(year,1,1);leap=year%4==0&&year%100||year%400==0;/*判闰年*/for(i=0;i<12;i++) for(j=0;j<6;j++) for(k=0;k<7;k++) date[i][j][k]=0;/*日期表置0*/for(i=0;i<12;i++)/*一年十二个月*/ for(wd=0,day=1;day<=day_tbl[leap][i];day++) date[i][wd][sw]=day; sw=++sw%7;/*每星期七天，以0至6计数*/ if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/ } printf("\n|==================The Calendar of Year %d =====================|\n|",year);for(i=0;i<6;i++) for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/ wd+=date[i][5][k]+date[i+6][5][k]; wd=wd?6:5; printf("%2d %s %2d %s |\n|",i+1,title,i+7,title); for(j=0;j<wd;j++) printf(" ");/*输出四个空白符*/ /*左栏为第i+1月，右栏为第i+7月*/ for(k=0;k<7;k++) if(date[i][j][k]) printf("%4d",date[i][j][k]); else printf(" "); printf(" ");/*输出十个空白符*/ for(k=0;k<7;k++) if(date[i+6][j][k]) printf("%4d",date[i+6][j][k]); else printf(" "); printf(" |\n|"); } /*scanf("%*c");/*键入回车输出下一个月的日历*/ }puts("=================================================================|");puts("\n Press any key to quit...");getch();}

C语言程序设计万年历打印设计

4，电子万年历用C语言设计一个年历系统功能要求 1输入任一

//这个可以吧#include "stdio.h"long int f(int year,int month) if(month<3) return year-1; else return year;}long int g(int month) if(month<3) return month+13; else return month+1;}long int n(int year,int month,int day) /*N=1461*f(年、月)/4+153*g(月)/5+日*/ return 1461L*f(year,month)/4+153L*g(month)/5+day;}int w(int year,int month,int day) /*w=(N-621049)%7(0<=w<7)*/ return(int)((n(year,month,day)%7-621049L%7+7)%7);}int date[12][6][7];int day_tbl[ ][12]= main() int year;/*年*/ char title[]="SUN MON TUE WED THU FRI SAT";clrscr();printf("Please input the year whose calendar you want to know: ");/*输入年*/scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/sw=w(year,1,1);leap=year%4==0&&year%100||year%400==0;/*判闰年*/for(i=0;i<12;i++) for(j=0;j<6;j++) for(k=0;k<7;k++) date[i][j][k]=0;/*日期表置0*/for(i=0;i<12;i++)/*一年十二个月*/ for(wd=0,day=1;day<=day_tbl[leap][i];day++) date[i][wd][sw]=day; sw=++sw%7;/*每星期七天，以0至6计数*/ if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/ } printf("\n|==================The Calendar of Year %d =====================|\n|",year);for(i=0;i<6;i++) for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/ wd+=date[i][5][k]+date[i+6][5][k]; wd=wd?6:5; printf("%2d %s %2d %s |\n|",i+1,title,i+7,title); for(j=0;j<wd;j++) printf(" ");/*输出四个空白符*/ /*左栏为第i+1月，右栏为第i+7月*/ for(k=0;k<7;k++) if(date[i][j][k]) printf("%4d",date[i][j][k]); else printf(" "); printf(" ");/*输出十个空白符*/ for(k=0;k<7;k++) if(date[i+6][j][k]) printf("%4d",date[i+6][j][k]); else printf(" "); printf(" |\n|"); } /*scanf("%*c");/*键入回车输出下一个月的日历*/}puts("=================================================================|");puts("\n Press any key to quit...");getch();}

我是楼主，找到这个，但是显示不完，谁能调试好，显示出前面的，也行。#include <stdio.h>long int f(int year,int month) if(month<3) return year-1; else return year;}long int g(int month) if(month<3) return month+13; else return month+1;}long int n(int year,int month,int day) return 1461L*f(year,month)/4+153L*g(month)/5+day;}int w(int year,int month,int day) return(int) ((n(year,month,day)%7-621049L%7+7)%7);}int date[12][6][7];int day_tbl[ ][12]=main() int sw,leap,i,j,k,wd,day; int year; char title[]="SUM MON TUE WED THU FRI SAT"; printf("Please input the year whose calendar you want to know:\n"); scanf("%d%*c",&year); sw=w(year,1,1); leap=year%4==0&&year%100||year%400==0; for(i=0;i<12;i++) for(j=0;j<6;j++) for(k=0;k<7;k++) date[i][j][k]=0; for(i=0;i<12;i++) for(wd=0,day=1;day<=day_tbl[leap][i];day++) date[i][wd][sw]=day; sw=++sw%7; if(sw==0) wd++; } printf("\n|================== The Calendar of Year %d==================|\n|",year); for(i=0;i<6;i++) for(wd=0,k=0;k<7;k++) wd+=date[i][5][k]+date[i+6][5][k]; wd=wd?6:5; printf(" %2d %s %2d %s|\n|",i+1,title,i+7,title); for(j=0;j<wd;j++) printf(" "); for(k=0;k<7;k++) if(date[i][j][k]) printf("%4d",date[i][j][k]); else printf(" "); printf(" "); for(k=0;k<7;k++) if(date[i+6][j][k]) printf("%4d",date[i+6][j][k]); else printf(" "); printf("|\n|"); } } puts("==============================================================|");getch();}

两个月并排显示也太变态了，这个是各个月连续显示的。#include <stdio.h> #include <conio.h> #include <stdlib.h> #include <time.h> int leap(int year ) if ((year %4 == 0) && (year % 100 != 0) || (year % 400 == 0)) return 1; } return 0; } void show(int year,int month) const char month_str[][4]="May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"}; const int month_day[]=int i,j,wdays,mdays,days; int count=0;for(i=1,days=0;i<year;i++) if(leap(i)) days += 366; } else days += 365; } } for(i=1;i<month;i++) if(i==2 && leap(year)) days+=29; } else days+=month_day[i]; } } printf("\n----------------------------\n"); printf(" %s %d\n",month_str[month],month); printf(" Sun Mon Tue Wed Thu Fri Sat\n"); wdays = days % 7; for( j = 0; j <= wdays; j++) if(wdays==6) break;for( i = 0; i < 4; i++) printf(" ");} count++;} if(month == 2 && leap(year)) mdays=29; } else mdays= month_day[month]; } for(i=1;i<=mdays;i++) if( i > 1 && count % 7 == 0 ) printf("\n"); } printf("%4d",i); count++; } printf("\n----------------------------\n"); } main() int year,month; printf("Input the year:");scanf("%d",&year);printf("The calendar of the year %d.",year); printf("\n----------------------------\n"); for(month=1;month<=12;month++)show(year,month); system("pause");}